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Hikaru
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« on: July 23, 2006, 09:37:23 PM »
ok... I got this extremly annoying limit to solve... Karin if you know something.. (or anyone else who happens to know something about limits)

I believe it is either 0 or 1 or nothing at all.
« Last Edit: July 23, 2006, 09:43:44 PM by Uriku » Logged

Hikaru
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« Reply #1 on: July 24, 2006, 12:48:49 PM »
lim (1+x)^(1/x^2) = oo
x->0

it is lim x->0 (1+x)^(1/x) = e
well I tried to graph it, and for 2.7=s->e (couldn't put e in there.... damn graph sketchers)
I got


however, for 2.71828183 = s->e
I got

must be something like 1/sqrt(e) or someething.

OK! solution!
it seems it is 1/sqrt(e).
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« Reply #2 on: July 24, 2006, 05:54:40 PM »
Darn , I'm the worst Maths here.
The Day After Tomorrow will be my Maths exam but my mind still empty. (x...x)

Hate Maths .....
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Hikaru
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« Reply #3 on: July 24, 2006, 06:10:41 PM »
@_@

what kind of math?
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« Reply #4 on: July 24, 2006, 06:16:34 PM »
Quote from: Uriku on July 24, 2006, 06:10:41 PM
@_@

what kind of math?

Eh...Add Maths.
Once I saw alots of Numbers , my head will started to turn around. (@.@)
Darn , bad until can get 0% for it (-.-!!)
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Hikaru
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« Reply #5 on: July 24, 2006, 06:53:15 PM »
I managed to solve it (posted above.. I guess you haven't seen it)
just force it to look like the definition of e and it should work out.

solution
I was told that doing L'hopital 3 times works too, but meh, it's annoying.
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Hikaru
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« Reply #6 on: July 24, 2006, 11:35:56 PM »
this method is usefull, especially considering that it came before l'hopital.
I tried to solve this


and after a while of l'hopitaling I thought "hey! if it worked for the last one why can't it work here?", so I did it again here and it worked alot better.

as my teacher always says, l'hopital is like a super cannon, but it's so strong that you might not want to use it.
sure, it can make problems like

a crapload simplier, but it can get to some pretty annoying dead ends or just extremely complicated paths.

oops I have an error, that's simple even without l'hopital.
however...

is much more difficult.

as for an explanation to what a limit is I posted it some time ago, but I guess it was in the Spam Thread.
in short it's where the function should go at a point, ignoring the value the function actually has at that point.
for example x^2/x has a limit at (0,0), though x^2/x is not defined at that point.
« Last Edit: July 25, 2006, 08:10:13 AM by Plasmacaster » Logged

Hikaru
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« Reply #7 on: July 25, 2006, 12:15:50 PM »
OK found some derivatives calcultors.
this one is very usefull, mainly because after solving it simplifies the answer, so you're won't get stuck with something huge and an workable.
I also found this.
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Hikaru
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« Reply #8 on: July 25, 2006, 09:13:18 PM »
meh I think there is one for integrals.
google is your friend - it finds all.
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Orion
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« Reply #9 on: August 02, 2006, 02:04:49 PM »
Here is somthing that may interest you "math heads" Smiley

Moving Sofa Constant
« Last Edit: August 02, 2006, 02:37:35 PM by Orion » Logged

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Hikaru
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« Reply #10 on: August 02, 2006, 05:19:25 PM »
yea... math is everywhere!
from compacting oranges in the least amount of space to modular shapes, math tries to solves everything solveable.

lol wtf is that movie?! it makes no sense what so ever.
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Hikaru
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« Reply #11 on: August 02, 2006, 09:40:12 PM »
don't worry - it makes no sense.
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Orion
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« Reply #12 on: August 02, 2006, 10:26:15 PM »
It's suppose to be funny. Smiley
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« Reply #13 on: September 23, 2006, 01:16:14 PM »
[ ] Ba(OH)2 + [2]HNO3 --> [ ] Ba(NO3)2 + [2] H2O

that's just lazy!
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Hikaru
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« Reply #14 on: September 23, 2006, 01:21:29 PM »
it's a linear set of homogeneous equations.

[ a ] Ba(OH)2 + [ b ]HNO3 --> [ c ] Ba(NO3)2 + [ d ] H2O
Ba: 1a        = 1c
H:  2a + 3b = 2c + 2d
O:  2a + 1b =     + 1d
N:          1b = 2c

and remember, the triviall solution always exists: 0everything --> 0everything
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